So considering most draws are slightly above or below 1% it's a wash? I guess I would rather a 6% chance on 1 hunt than a 1% chance on 6 hunts.
As z987k says, you obviously have a higher draw odds for that one tag you put 6 chances in for than if you put fewer chances in for that tag.
That said, if you were looking at 6 tags, each with exactly an x% draw chance, you would have the same odds of drawing *a tag* by putting one chance in for each of those 6 tags, or all 6 chances in for one of the tags…. or whichever combination of those 6 choices and 6 tags you choose. The odds are the same. Assuming all of the tags have equal probability of draw to one another.
The formula for overall draw odds is also not just additive. For example, if you have a tag with a 25% draw odds (let’s say 25 tags and 100 applications) you can’t just add 25/100 6 times (25/100*6) to get your draw odds. You can’t have a 150% draw odds. The correct calculation is as follows (this is not exact because reasons, but this is a close approximation):
x = # of tags available
y = # of individual draw applications for that tag
n = # of times you put in for that tag (between 1 and 6)
(tag draw odds) = 1 - ((1-(x/y))^n)
or
(tag draw odds) = 1 - ((1-(n/y))^x)
I’m not actually sure which of these two equations is correct, but they will come to approximately the same answer.
edit: I should add that this is both an approximation of your odds (the odds are slightly higher in reality because with each subsequent draw, one application is removed from the pool), but also this can only be estimated using *last years’* numbers. There is no way to know how many applications (or sometimes, how many tags) will go for any specific tag in the current year, so this is the best proxy you will get.